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Question

Question
If a sample of 20mL of water is heated from 7°C to 98°C , what is the energy content of the water?

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Answer

Q = (20 g)(4.184 J/g^{\circ}C)(98^{\circ}C - 7^{\circ}C) = 7990.4 JQ = (20 g)(4.184 J/g^{\circ}C)(98^{\circ}C - 7^{\circ}C) = 7990.4 J

Explanation

Step1: Calculate the temperature change The temperature change is the difference between the final temperature and the initial temperature. Step2: Calculate the energy content The energy content is calculated using the formula: Q = mc\Delta TQ = mc\Delta T, where Q is the energy content, m is the mass of the water, c is the specific heat capacity of water, and \Delta T\Delta T is the temperature change.

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