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Subtract using hundredth a 5.46 3.59 square D

Asked By GoldenEagle31 at

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John

Expert · 1.0k answers · 1k people helped

Answer

First, let's write the problem in a way that's easier to understand and process. We want to subtract 3.59 from 5.46.Let's setup our problem for subtraction. \begin{array}{ r } 5.46 \\ - 3.59 \\ \hline ?\end{array} Ensure to align the problem correctly. The decimal point should be in the same position for both numbers; this will make our calculation more accurate.Subtracting the tenth and hundredth places:6 (in the hundredths place of 5.46) minus 9 (in the hundredths place of 3.59) we can't do directly because 6 is less than 9. Therefore, we need to borrow 1 from the tenth place. 1.6 or 16 (in terms of hundredths) minus 9 gives 7.4 (in the tenths place of the 5.46, originally, but we had borrowed 1, so it's now 3) minus 5 (in the tenths place of 3.59), similar to the previous step, we can't do because 3 is less than 5. So, we need to borrow 1 from the ones place. 1.3 or 13 (in terms of tenths) minus 5 gives 8.5 (in the ones place of 5.46, but we have borrowed 1, so it's now 4) minus 3 (in the ones place of 3.59) gives us 1.So, combining these together our calculation becomes: \begin{array}{ r } 5.46 \\ - 3.59 \\ \hline 1.87 \end{array} so, the answer to 5.46 - 3.59 is 1.87Going back to our problem, we find that the solution is: 5.46 - 3.59 = \boxed{1.87}.

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